For a 240-volt, single-phase circuit supplying a continuous load of 5 kilowatts and a non-continuous load of 6 kilowatts, what is the minimum standard size inverse-time circuit breaker required?

To determine the minimum size of the inverse-time circuit breaker for a single-phase circuit with both continuous and non-continuous loads, it's essential to follow the National Electrical Code (NEC) guidelines.

First, we calculate the total load on the circuit. The continuous load is specified as 5 kilowatts, and the non-continuous load is 6 kilowatts. According to NEC rules, the continuous load should be multiplied by 125% to account for potential overloads. Thus, the calculation proceeds as follows:

1. Convert the kilowatt values to amperes using the formula:

[

\text{Amperes} = \frac{\text{Watts}}{\text{Volts}}

]

2. The continuous load in amperes:

[

5,000 \text{ watts} / 240 \text{ volts} = 20.83 \text{ amps}

]

Since this is a continuous load, we multiply by 1.25:

[

20.83 \text{ amps} \times 1.25 = 26.04 \text{ amps}

]

3. The non-continuous